Answer:
Given velocity, \[v=4.0\,m/s\]
Acceleration \[a=1.2m/{{s}^{2}}\]
time, t = 5.0 seconds
we know, distance travelled
\[a=ut+\frac{1}{2}a{{t}^{2}}=4.0\times 5.0=\frac{1}{2}\times 1.2{{(5.0)}^{2}}\]
\[=20.0+25.0\times 0.6=20.0+15.0=35.0m\]
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