Answer:
The distance travelled by car ‘P’
= Area of triangle ‘OAB’
\[=\frac{1}{2}\times OB\times AB=\frac{1}{2}\times 10\times 30=175m\]
Distance travelled by car Q
= Area of trapezium CDEB
\[=\frac{1}{2}\times EB\times (DE+CB)=\frac{1}{2}\times 25\times (5+8)\]
\[=162.5m\]
car ‘P’ is ahead by = (175 - 162.5) m = 12.5 m
\[150=10u+\frac{1}{2}a{{(10)}^{2}}\] car P is ahead by 12.5 m.
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