Answer:
\[Average\,velocity=\frac{total\,\,displacement}{total\,time\,\,taken}\]
\[{{V}_{ave}}=\frac{{{s}_{1}}+{{s}_{2}}}{{{t}_{1}}+{{t}_{2}}}\]
\[{{s}_{1}}={{v}_{1}}{{t}_{1}}\,\,\And \,\,{{s}_{2}}={{v}_{2}}{{t}_{2}}\,\,\sin ce\,\,t={{t}_{1}}={{t}_{1}}\]
\[{{v}_{ave}}=\frac{{{v}_{1}}t+{{v}_{2}}t}{t+t}=\frac{[{{v}_{1}}+{{v}_{2}}]}{2t}=\frac{{{v}_{1}}+{{v}_{2}}}{2}\]
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