A) 2.0 and 3.0 sec
B) Only at 3.0 sec
C) Only at 2.0 sec
D) After 1 and 2 sec
Correct Answer: A
Solution :
\[h=ut-\frac{1}{2}g{{t}^{2}}\Rightarrow 96=80t-\frac{32}{2}{{t}^{2}}\] \[\Rightarrow {{t}^{2}}-5t+6=0\Rightarrow t=2\]sec or 3 sec
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