JEE Main & Advanced Physics Motion in a Straight Line / सरल रेखा में गति Question Bank Motion Under Gravity

  • question_answer
    A particle is dropped under gravity from rest from a height \[h(g=9.8\,m/{{\sec }^{2}})\] and it travels a distance \[9h/25\] in the last second, the height \[h\] is                         [MNR 1987]

    A)             100 m 

    B)             122.5 m

    C)             145 m

    D)             167.5 m

    Correct Answer: B

    Solution :

                    Let h distance is covered in n sec             \[\Rightarrow h=\frac{1}{2}g{{n}^{2}}\]                          ?(i)             Distance covered in \[{{n}^{th}}\]sec\[=\frac{1}{2}g(2n-1)\]             \[\Rightarrow \frac{9h}{25}=\frac{g}{2}(2n-1)\]                              ?(ii)             From (i) and (ii), \[h=122.5\ m\]


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