A) 2.50 m
B) 3.75 m
C) 4.00 m
D) 1.25 m
Correct Answer: B
Solution :
Time taken by first drop to reach the ground \[t=\sqrt{\frac{2h}{g}}\] \[\Rightarrow \ \ t=\sqrt{\frac{2\times 5}{10}}\]\[=1\ \sec \] As the water drops fall at regular intervals from a tap therefore time difference between any two drops \[=\frac{1}{2}\ \sec \] In this given time, distance of second drop from the tap\[=\frac{1}{2}g{{\left( \frac{1}{2} \right)}^{2}}=\frac{5}{5}=1.25\,m\] Its distance from the ground \[=5-1.25=3.75\ m\]
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