A) It reaches \[H/2\] in \[T/2\] sec
B) It acquires velocity \[u/2\] in \[T/2\sec \]
C) Its velocity is \[u/2\] at \[H/2\]
D) Same velocity at \[2T\]
Correct Answer: B
Solution :
At maximum height velocity \[v=0\] We know that \[v=u+at\], hence \[0=u-gT\Rightarrow u=gT\] When \[v=\frac{u}{2}\], then \[\frac{u}{2}=u-gt\Rightarrow gt=\frac{u}{2}\Rightarrow gt=\frac{gT}{2}\Rightarrow t=\frac{T}{2}\] Hence at \[t=\frac{T}{2}\], it acquires velocity \[\frac{u}{2}\]
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