A) \[\sqrt{3}{{V}_{o}}\]
B) \[3{{V}_{o}}\]
C) \[9{{V}_{o}}\]
D) \[3/2{{V}_{o}}\]
Correct Answer: A
Solution :
\[{{H}_{\max }}\propto {{u}^{2}}\] \\[u\propto \sqrt{{{H}_{\max }}}\] i.e. to triple the maximum height, ball should be thrown with velocity \[\sqrt{3}\ u\].
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