A) \[{{\omega }_{\min }}=\sqrt{\frac{g}{\mu r}}\]
B) \[{{\omega }_{\min }}=\sqrt{\frac{\mu r}{g}}\]
C) \[{{\omega }_{\min }}=\sqrt{\frac{2g}{\mu r}}\]
D) \[{{\omega }_{\min }}=\sqrt{\frac{gr}{\mu }}\]
Correct Answer: A
Solution :
We known, \[\mu \times r=mg\] \[\therefore \] \[\mu \times m\omega 2r=mg\] \[\Rightarrow \] \[\omega =\sqrt{\frac{g}{ur}}\]You need to login to perform this action.
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