A) \[\frac{{{v}^{2}}b}{Rg}\]
B) \[\frac{vb}{Rg}\]
C) \[\frac{v{{b}^{2}}}{Rg}\]
D) \[\frac{vb}{{{R}^{2}}g}\]
Correct Answer: A
Solution :
Let \[\theta \] be the angle of banking to counteract the centrifugal force. Then \[\tan \theta =\frac{{{v}^{2}}}{rg}\] If \[x\] is the elevation required, then \[\sin \theta =\frac{x}{b}\] \[\Rightarrow \] \[\theta =\sin \theta \approx \tan \theta =\frac{x}{b}\] \[\therefore \] \[\frac{x}{b}=\frac{{{v}^{2}}}{Rg}\] \[\Rightarrow \] \[x=\frac{{{v}^{2}}b}{Rg}\]You need to login to perform this action.
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