A) 50 m
B) 40 m
C) 30 m
D) 20 m
Correct Answer: B
Solution :
In \[4\] seconds increases in velocity is\[5m/\sec \] Distance travelled between \[1\sec \] and\[4\sec \],\[s=\frac{1}{2}\times 3\times (11.25+15)=\mathbf{40}\,\,\mathbf{m}\]You need to login to perform this action.
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