A) \[\text{a cos t}\]
B) \[-\text{ a cos t}\]
C) \[\text{a sin t}\]
D) \[-\text{ a sin t}\]
Correct Answer: B
Solution :
\[S.H.M,\,\,x=a\cos \omega t\]and accelerations \[=-{{\omega }^{2}}x=-{{\omega }^{2}}a\cos \omega t\] Here\[\omega =1\], therefore acceleration\[=-\mathbf{acost}\]You need to login to perform this action.
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