A) 112 m/s
B) 11.2 m/s
C) \[\frac{0.64\times 20}{1000}m/s\]
D) \[\frac{1000}{0.64\times 20}m/s\]
Correct Answer: B
Solution :
\[{{v}_{\max }}=\sqrt{\mu gr}\]\[=\sqrt{0.64\times 9.4\times 20}=\mathbf{11}\mathbf{.2}\,\,\mathbf{m/s}\]You need to login to perform this action.
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