A) \[1.256\times {{10}^{-3}}\,V\]
B) \[6.28\times {{10}^{-4}}\,V\]
C) \[1.256\times {{10}^{-4}}\,V\]
D) \[6.28\times {{10}^{-5}}V\]
Correct Answer: D
Solution :
\[e=B{{l}^{2}}\pi \nu =0.4\times {{10}^{-4}}\times {{(0.5)}^{2}}\times (3.14)\times \frac{120}{60}\] \[=6.28\times {{10}^{-5}}V\]You need to login to perform this action.
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