JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Motional EMI

  • question_answer
    A copper disc of radius 0.1 m is rotated about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla with its plane perpendicular to the field. The e.m.f. induced across the radius of disc is                [MH CET (Med) 2001]

    A)            \[\frac{\pi }{10}\ V\]         

    B)            \[\frac{2\pi }{10}\ V\]

    C)            \[\pi \times {{10}^{-2}}V\]     

    D)            \[2\pi \times {{10}^{-2}}V\]

    Correct Answer: C

    Solution :

               \[e=\frac{1}{2}B\omega {{r}^{2}}=\frac{1}{2}\times 0.1\times 2\pi \times 10\times {{(0.1)}^{2}}\]\[=\pi \times {{10}^{-2}}V\]


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