A) 0
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
Let \[\overrightarrow{A}=2\hat{i}+3\hat{j}-\hat{k}\] and \[\overrightarrow{B}=-4\hat{i}-6\hat{j}+\lambda \hat{k}\] \[\overrightarrow{A}\] and \[\overrightarrow{B}\] are parallel to each other \[\frac{{{a}_{1}}}{{{b}_{1}}}=\frac{{{a}_{2}}}{{{b}_{2}}}=\frac{{{a}_{3}}}{{{b}_{3}}}\] i.e. \[\frac{2}{-4}=\frac{3}{-6}=\frac{-1}{\lambda }\]\[\Rightarrow \,\,\lambda =2\].
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