JEE Main & Advanced Physics Vectors Question Bank Multiplication of Vectors

  • question_answer
    The resultant of the two vectors having magnitude 2 and 3 is 1. What is their cross product 

    A)                 6             

    B)                 3

    C)                 1             

    D)                 0

    Correct Answer: D

    Solution :

                        \[\sqrt{{{2}^{2}}+{{3}^{2}}+2\times 2\times 3\times \cos \theta }=1\] By solving we get\[\theta =180{}^\circ \]\ \[\vec{A}\times \vec{B}=0\]


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