JEE Main & Advanced Physics Vectors Question Bank Multiplication of Vectors

  • question_answer
    The angle between two vectors given by \[6\bar{i}+6\bar{j}-3\bar{k}\] and \[7\overline{i}+4\overline{j}+4\overline{k}\] is                  [EAMCET (Engg.) 1999]

    A)                 \[{{\cos }^{-1}}\left( \frac{1}{\sqrt{3}} \right)\]

    B)                             \[{{\cos }^{-1}}\left( \frac{5}{\sqrt{3}} \right)\]

    C)                 \[{{\sin }^{-1}}\left( \frac{2}{\sqrt{3}} \right)\]  

    D)                 \[{{\sin }^{-1}}\left( \frac{\sqrt{5}}{3} \right)\]

    Correct Answer: D

    Solution :

                        \[\cos \theta =\frac{\vec{A}\vec{B}}{AB}=\frac{42+24-12}{\sqrt{36+36+9}\sqrt{49+16+16}}\]\[=\frac{56}{9\sqrt{71}}\]                 \[\cos \theta =\frac{56}{9\sqrt{71}}\] \ \[\sin \theta =\frac{\sqrt{5}}{3}\] or \[\theta ={{\sin }^{-1}}\left( \frac{\sqrt{5}}{3} \right)\]


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