A) Perpendicular
B) Parallel
C) Antiparallel
D) Inclined at an angle of \[\text{6}0{}^\circ \]
Correct Answer: D
Solution :
\[\overrightarrow{AB}=(4\hat{i}+5\hat{j}+6\hat{k})-(3\hat{i}+4\hat{j}+5\hat{k})\]=\[\hat{i}+\hat{j}+\hat{k}\] \[\overrightarrow{CD}=(4\hat{i}+6\hat{j})-(7\hat{i}+9\hat{j}+3\hat{k})\] \[=-3\hat{i}-3\hat{j}-3\hat{k}\] \[\overrightarrow{AB}\] and \[\overrightarrow{CD}\] are parallel, because its cross-products is 0.
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