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JEE Main & Advanced Physics Vectors Question Bank Multiplication of Vectors

  • question_answer
    A particle moves from position \[3\hat{i}+2\hat{j}-6\hat{k}\] to \[14\hat{i}+13\hat{j}+9\hat{k}\] due to a uniform force of \[(4\hat{i}+\hat{j}+3\hat{k})\,N.\] If the displacement in meters then work done will be [CMEET 1995; Pb. PMT 2002, 03]

    A)                  100 J    

    B)                 200 J

    C)                 300 J     

    D)                 250 J

    Correct Answer: A

    Solution :

                        \[S=\overrightarrow{{{r}_{2}}}-\overrightarrow{{{r}_{1}}}\]                 \[W=\overrightarrow{F}\,.\,\overrightarrow{S}\] \[=(4\hat{i}+\hat{j}+3\hat{k})\,.\,(11\hat{i}+11\hat{j}+15\hat{k})\]                 \[=(4\times 11+1\times 11+3\times 15)\,=100\,J.\]


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