A) \[\overrightarrow{A}+\overrightarrow{B}=0\]
B) \[\overrightarrow{A}-\overrightarrow{B}=0\]
C) \[\overrightarrow{A}\times \overrightarrow{B}=0\]
D) \[\overrightarrow{A}\,.\,\overrightarrow{B}=0\]
Correct Answer: D
Solution :
\[\vec{A}.\vec{B}=\,|\vec{A}|.|\vec{B}|.\cos \theta =\vec{A}.\vec{B}.\cos 90{}^\circ =0\]You need to login to perform this action.
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