A) 1 m/s, 3.5 m/s
B) 1 m/s, 3 m/s
C) 2 m/s, 4 m/s
D) 1.5 m/s, 3 m/s
Correct Answer: B
Solution :
[b] |
\[\text{v=-6m}{{\text{s}}^{-1}}\] |
Acceleration \[a=\frac{6-0}{1}=6m{{s}^{-2}}\] |
For \[t=0\] to \[t=1\]s, |
\[{{S}_{1}}=\frac{1}{2}\times 6{{(1)}^{2}}=3m\] (i) |
For \[t=1\] s to \[t=2\] s, |
\[{{S}_{2}}=6.1-\frac{1}{2}\times 6{{(1)}^{2}}=3m\] (ii) |
For \[t=2s\] to \[t=3s\], |
\[{{S}_{3}}=0-\frac{1}{2}\times 6{{(1)}^{2}}=-3m\] (iii) |
Total displacement \[\text{S=}{{\text{S}}_{\text{1}}}\text{+}{{\text{S}}_{\text{2}}}\text{+}{{\text{S}}_{\text{3}}}\text{=3m}\] |
Average velocity\[\text{=}\frac{\text{3}}{\text{3}}\text{=1m}{{\text{s}}^{\text{-1}}}\] |
Total distance travelled \[\text{=9m}\] |
Average speed\[\text{=}\frac{9}{3}=3m{{s}^{-1}}\] |
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