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NEET Physics Electrostatics & Capacitance Question Bank NEET PYQ - Electrostatics and Capacitance

  • question_answer
    Two point charges A and B, having charges +Q and –Q respectively, are placed at certain distance apart and force acting between them is F. If 25 % charge of A is transferred to B, then force between the charges becomes-                   [NEET 2019]

    A) \[\frac{16F}{9}\]

    B) \[\frac{4F}{3}\]

    C) F

    D) \[\frac{9F}{16}\]

    Correct Answer: D

    Solution :

    [d] \[F=\frac{KQQ}{{{r}^{2}}}\] \[F'=\frac{K\frac{3Q}{4}\times \frac{3Q}{4}}{{{r}^{2}}}=\frac{9F}{16}\]


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