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question_answer1) Read the assertion and reason carefully to mark the correct option out of the options given below: If both assertion and reason are true and the reason is the correct explanation of the assertion. If both assertion and reason are true but reason is not the correct explanation of the assertion. If assertion is true but reason is false. If the assertion and reason both are false. If assertion is false but reason is true Assertion: \[S{{O}_{2}}\] and \[C{{l}_{2}}\] both are bleaching agents. Reason: Both are reducing agents. [AIIMS 1995]
question_answer2) Assertion: Fluorine exists only in ?1 oxidation state. Reason: Fluorine has \[2{{s}^{2}}2{{p}^{5}}\] configuration. [AIIMS 2001]
question_answer3) Assertion: Stannous chloride is a powerful oxidising agent which oxidises mercuric chloride to mercury. Reason: Stannous chloride gives grey precipitate with mercuric chloride, but stannic chloride does not do so. [AIIMS 2002]
question_answer4) Assertion: \[HCl{{O}_{4}}\] is a stronger acid than \[HCl{{O}_{3}}\]. Reason: Oxidation state of \[Cl\] in \[HCl{{O}_{4}}\] is +VII and in \[HCl{{O}_{3}}\]+V. [AIIMS 2004]
question_answer5) Assertion: In a reaction \[Zn(s)+CuS{{O}_{4}}(aq)\to \] \[ZnS{{O}_{4}}(aq)+Cu(s)\], \[Zn\] is a reductant but itself get oxidized. Reason: In a redox reaction, oxidant is reduced by accepting electrons and reductant is oxidized by losing electrons.
question_answer6) Assertion: Oxidation number of carbon in \[C{{H}_{2}}O\] is zero. Reason: \[C{{H}_{2}}O\] formaldehyde, is a covalent compound.
question_answer7) Assertion: The oxidation numbers are artificial, they are useful as a ?book-keeping? device of electrons in reactions. Reason: The oxidation numbers do not usually represent real charges on atoms, they are simply conventions that indicate what the maximum charge could possibly be on an atom in a molecule.
question_answer8) Assertion: \[{{H}_{2}}S{{O}_{4}}\] cannot act as reducing agent. Reason: Sulphur cannot increase its oxidation number beyond + 6.
question_answer9) Assertion: Equivalent weight of \[N{{H}_{3}}\] in the reaction \[{{N}_{2}}\to N{{H}_{3}}\] is 17/3 while that of \[{{N}_{2}}\] is 28/6. Reason: Equivalent weight =\[\frac{\text{Molecular weight}}{\text{number of }{{e}^{}}\text{lost or gained}}\].
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