A) \[v=\frac{1}{2R}\sqrt{\frac{1}{Gm}}\]
B) \[v=\sqrt{\frac{Gm}{2R}}\]
C) \[v=\frac{1}{2}\sqrt{\frac{Gm}{R}}\]
D) \[v=\sqrt{\frac{4Gm}{R}}\]
Correct Answer: C
Solution :
Centripetal force provided by the gravitational force of attraction between two particles i.e. \[\frac{m{{v}^{2}}}{R}=\frac{Gm\times m}{{{(2R)}^{2}}}\] \[\Rightarrow v=\frac{1}{2}\sqrt{\frac{Gm}{R}}\]You need to login to perform this action.
You will be redirected in
3 sec