A) Hydrocyanic acid
B) Ammonia
C) Ammonium cyanide
D) Urea
Correct Answer: D
Solution :
\[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}+KCNO\to \]\[N{{H}_{4}}CNO+{{K}_{2}}S{{O}_{4}}\to \underset{\text{Urea}}{\mathop{N{{H}_{2}}-CO-N{{H}_{2}}}}\,\]You need to login to perform this action.
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