A) Heating \[N{{H}_{4}}N{{O}_{2}}\]
B) Heating \[N{{H}_{4}}N{{O}_{3}}\]
C) Treating \[{{H}_{2}}{{O}_{2}}\] with \[NaN{{O}_{2}}\]
D) Treating \[M{{g}_{3}}{{N}_{2}}\] with \[{{H}_{2}}O\]
Correct Answer: A
Solution :
\[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow{\Delta }{{N}_{2}}\uparrow +C{{r}_{2}}{{O}_{3}}+4{{H}_{2}}O\] \[N{{H}_{4}}N{{O}_{2}}\xrightarrow{\Delta }{{N}_{2}}\uparrow +2{{H}_{2}}O\]You need to login to perform this action.
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