A) + 1
B) + 2
C) + 3
D) + 4
Correct Answer: B
Solution :
\[[\underset{x}{\mathop{Pt}}\,\underset{0}{\mathop{({{C}_{2}}}}\,{{H}_{4}})\underset{-1}{\mathop{C{{l}_{3}}}}\,{{]}^{-}}\] \[x+0+3x(-1)=-1\], \[x-3=-1,\] \[x=+2.\]You need to login to perform this action.
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