A) \[2m/{{\sec }^{2}}\]
B) \[2.7m/{{\sec }^{2}}\]
C) \[1.8m/{{\sec }^{2}}\]
D) \[9.8\,m/{{\sec }^{2}}\]
Correct Answer: B
Solution :
Net acceleration in nonuniform circular motion, a\[=\sqrt{a_{t}^{2}+a_{c}^{2}}\]\[=\sqrt{{{(2)}^{2}}+{{\left( \frac{900}{500} \right)}^{2}}}=2.7\,m/{{s}^{2}}\] \[{{a}_{t}}=\]tangential acceleration \[{{a}_{c}}=\]centripetal acceleration \[=\frac{{{v}^{2}}}{r}\]
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