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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Non-uniform Circular Motion

  • question_answer
    The string of pendulum of length \[l\] is displaced through \[{{90}^{o}}\] from the vertical and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is                                                  [MP PMT 1986]

    A)             \[mg\]

    B)                      \[3mg\]

    C)             \[5\,mg\]          

    D)             \[6\,mg\]

    Correct Answer: B

    Solution :

                    \[T=mg+\frac{m{{v}^{2}}}{l}\] \[=mg+2mg=3mg\]              where \[v=\sqrt{2gl}\] from \[\frac{1}{2}m{{v}^{2}}=mgl\]


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