A) \[2\,mg\]
B) \[mg\]
C) \[3mg\]
D) \[\sqrt{3}mg\]
Correct Answer: A
Solution :
When body is released from the position p (inclined at angle q from vertical) then velocity at mean position \[v=\sqrt{2gl(1-\cos \theta )}\] \ Tension at the lowest point = \[mg+\frac{m{{v}^{2}}}{l}\] \[=mg+\frac{m}{l}[2gl(1-\cos 60)]\]\[=mg+mg=2mg\]You need to login to perform this action.
You will be redirected in
3 sec