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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Non-uniform Circular Motion

  • question_answer
    If the equation for the displacement of a particle moving on a circular path is given by \[(\theta )=2{{t}^{3}}+0.5\], where \[\theta \] is in radians and \[t\] in seconds, then the angular velocity of the particle after 2 sec from its start is                    [AIIMS 1998]

    A)             8 rad/sec

    B)                      12 rad/sec

    C)             24 rad/sec

    D)                      36 rad/sec

    Correct Answer: C

    Solution :

                    \[\omega =\frac{d\theta }{dt}=\frac{d}{dt}(2{{t}^{3}}+0.5)=6{{t}^{2}}\]   at t =2 s, \[\omega =6\times {{(2)}^{2}}=24rad/s\]


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