JEE Main & Advanced Physics Two Dimensional Motion Question Bank Non-uniform Circular Motion

  • question_answer
    A body of mass \[m\] hangs at one end of a string of length l, the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of \[{{60}^{o}}\] with the vertical. The tension in the string at mean position is                                   [ISM Dhanbad 1994]

    A)             \[2\,mg\]

    B)                      \[mg\]

    C)             \[3mg\]

    D)             \[\sqrt{3}mg\]

    Correct Answer: A

    Solution :

                    When body is released from the position p (inclined at angle q from vertical) then velocity at mean position             \[v=\sqrt{2gl(1-\cos \theta )}\]             \ Tension at the lowest point = \[mg+\frac{m{{v}^{2}}}{l}\]             \[=mg+\frac{m}{l}[2gl(1-\cos 60)]\]\[=mg+mg=2mg\]


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