A) \[10\,\pi \,rad/\sec \]
B) \[20\,\pi \,rad/\sec \]
C) \[40\,\pi \,rad/\sec \]
D) \[60\,\pi \,rad/\sec \]
Correct Answer: B
Solution :
Increment in angular velocity \[\omega =2\pi ({{n}_{2}}-{{n}_{1}})\] \[\omega =2\pi (1200-600)\frac{rad}{min}=\frac{2\pi \times 600}{60}\frac{rad}{s}\]\[=20\pi \frac{rad}{s}\]
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