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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Non-uniform Circular Motion

  • question_answer
    A body of mass 1 kg is moving in a vertical circular path of radius 1m. The difference between the kinetic energies at its highest and lowest position is     

    A)             20J

    B)                      10J

    C)                         \[4\sqrt{5}J\]              

    D)                         \[10\left( \sqrt{5}-1 \right)J\]

    Correct Answer: A

    Solution :

                    Difference in kinetic energy = \[2mg\,r=2\times 1\times 10\times 1=20J\]


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