2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Two Dimensional Motion

JEE Main & Advanced Physics Two Dimensional Motion Question Bank Non-uniform Circular Motion

  • question_answer
            A wheel is subjected to uniform angular acceleration about its axis. Initially its angular velocity is zero. In the first 2 sec, it rotates through an angle \[{{\theta }_{1}}\]. In the next 2 sec, it rotates through an additional angle \[{{\theta }_{2}}\]. The ratio of \[\sqrt{3}mg\] is                                      [AIIMS 1985]

    A)             1

    B)                      2

    C)             3         

    D)             5

    Correct Answer: C

    Solution :

                    Using relation \[\theta ={{\omega }_{0}}t+\frac{1}{2}a{{t}^{2}}\]       \[{{\theta }_{1}}=\frac{1}{2}(\alpha ){{(2)}^{2}}=2\alpha \]    ?(i)  (As \[{{\omega }_{0}}=0,t=2\,\sec \]) Now using same equation for t = 4 sec, w0 = 0 \[{{\theta }_{1}}+{{\theta }_{2}}=\frac{1}{2}\alpha {{(4)}^{2}}=8\alpha \]              ?(ii) From (i) and (ii),\[{{\theta }_{1}}=2\alpha \]and\[{{\theta }_{2}}=6\alpha \]\ \[\frac{{{\theta }_{2}}}{{{\theta }_{1}}}=3\]


You need to login to perform this action.
You will be redirected in 3 sec spinner