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JEE Main & Advanced Physics Two Dimensional Motion Question Bank Non-uniform Circular Motion

  • question_answer
    A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m/sec. The tension in the string is 6 N, when the stone is at (g = 10 m/sec2) [AIIMS 1982]

    A)             Top of the circle          

    B)             Bottom of the circle

    C)             Half way down

    D)                      None of the above

    Correct Answer: A

    Solution :

                    \[mg=1\times 10=10N,\] \[\frac{m{{v}^{2}}}{r}=\frac{1\times {{(4)}^{2}}}{1}=16\] Tension at the top of circle = \[\frac{m{{v}^{2}}}{r}-mg=6N\] Tension at the bottom of circle = \[\frac{m{{v}^{2}}}{r}+mg=26N\]


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