A) 11.8 \[m/{{s}^{2}}\]
B) 11.0 \[m/{{s}^{2}}\]
C) 2.1 \[m/{{s}^{2}}\]
D) 0.8 \[m/{{s}^{2}}\]
Correct Answer: D
Solution :
Both trains will travel a distance of 1 km before to come in rest. In this case by using \[{{v}^{2}}={{u}^{2}}+2as\] \[\Rightarrow 0={{(40)}^{2}}+2a\times 1000\]\[\Rightarrow a=-0.8\ m/{{s}^{2}}\]You need to login to perform this action.
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