A)
B)
C)
D)
E)
Correct Answer: A
Solution :
The upper arrow rotates \[135{}^\circ \]CW in each step. The middle element gets laterally inverted in one step and its head gets replaced by a new symbol in the next step. The lower arrow rotates \[40{}^\circ \] ACW \[40{}^\circ \]CW, \[40{}^\circ \]CW, \[90{}^\circ \]ACW, \[90{}^\circ \]ACW ................... sequentially.You need to login to perform this action.
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