Answer:
The total number of protons and neutrons present inside a nucleus is called its mass number (A). The relation between the mass number (A) and radius (R) of the nucleus is \[R={{R}_{0}}{{A}^{1/3}},\] where \[{{R}_{0}}=1.1\times {{10}^{-15}}m\] Density of nuclear matter \[\rho =\frac{\text{Mass of}_{\text{1}}^{\text{1}}\text{ H}}{\text{Volume}}=\frac{1.66\times {{10}^{-27}}kg}{\frac{4}{3}\pi {{(1.1\times {{10}^{-15}}m)}^{3}}}\] \[=3\times {{10}^{17}}kg{{m}^{-3}}\] \[\frac{\text{Density of nuclear matter}}{\text{Density of ordinary matter}}=\frac{{{10}^{17}}}{{{10}^{3}}}=\mathbf{1}{{\mathbf{0}}^{\mathbf{14}}}\]
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