Answer:
The decays can be represented as follows : \[_{72}^{180}D\xrightarrow{_{2}^{4}He}_{70}^{176}\xrightarrow{_{-1}^{0}e}_{71}^{176}{{D}_{2}}\xrightarrow{_{2}^{4}He}_{69}^{172}{{D}_{3}}\] Nucleon number of \[\text{D }=\text{ 18}0\] Atomic number of \[\text{D }=\text{ 72}\] Nucleon number of \[{{\text{D}}_{3}}\text{ }=\text{172}\] Atomic number of \[{{\text{D}}_{3}}\text{ }=\text{ 69}\].
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