Answer:
No. of half-lives \[\text{=}\frac{\text{Time of disintegration}}{\text{Half-life period}}=\frac{72,000}{24,000}=3\] \[\therefore \] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{3}}=\frac{\mathbf{1}}{\mathbf{8}}\]
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