A) 4 Fermi
B) 5 Fermi
C) 6 Fermi
D) 8 Fermi
Correct Answer: C
Solution :
\[r\propto {{A}^{1/3}}\] Þ \[\frac{{{r}_{1}}}{{{r}_{2}}}={{\left( \frac{{{A}_{1}}}{{{A}_{2}}} \right)}^{1/3}}\] Þ \[\frac{3.6}{{{r}_{2}}}={{\left( \frac{27}{125} \right)}^{1/3}}=\frac{3}{5}\] Þ \[{{r}_{2}}=6\,Fermi\]You need to login to perform this action.
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