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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Nucleus, Nuclear Reaction

  • question_answer
    Radius of \[_{2}^{4}He\]nucleus is 3 Fermi. The radius of \[3\to 2\]nucleus will be                                             [CPMT 1999]

    A)            5 Fermi                                   

    B)            6 Fermi

    C)            11.16 Fermi                           

    D)            8 Fermi

    Correct Answer: C

    Solution :

                       We have \[r\propto {{A}^{1/3}}\Rightarrow \frac{{{r}_{2}}}{{{r}_{1}}}={{\left( \frac{{{A}_{2}}}{{{A}_{1}}} \right)}^{1/3}}={{\left( \frac{206}{4} \right)}^{1/3}}\]                    \[\therefore {{r}_{2}}=3{{\left( \frac{206}{4} \right)}^{1/3}}=11.6\ Fermi\].


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