A) An electron
B) A proton
C) A neutron
D) A neutrino
Correct Answer: D
Solution :
\[_{6}{{C}^{11}}{{\to }_{5}}{{B}^{11}}+{{\beta }^{+}}+\gamma \]because \[{{\beta }^{+}}{{=}_{1}}{{e}^{0}}\]You need to login to perform this action.
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