A) 1 MeV
B) 11.9 MeV
C) 23.8 MeV
D) 931 MeV
Correct Answer: C
Solution :
Mass of \[_{1}{{H}^{2}}=2.01478\ a.m.u.\] Mass of \[_{2}H{{e}^{4}}=4.00388\ a.m.u.\] Mass of two deuterium \[=2\times 2.01478=4.02956\] Energy equivalent to \[{{2}_{1}}{{H}^{2}}\] \[=4.02956\times 1.112\ MeV=4.48\ MeV\] Energy equivalent to \[_{2}{{H}^{4}}\] \[=4.00388\times 7.047\ MeV=28.21\ MeV\] Energy released\[=28.21-4.48=23.73\ MeV\]= 24 MeVYou need to login to perform this action.
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