A) 5 Fermi
B) 6 Fermi
C) 11.16 Fermi
D) 8 Fermi
Correct Answer: C
Solution :
We have \[r\propto {{A}^{1/3}}\Rightarrow \frac{{{r}_{2}}}{{{r}_{1}}}={{\left( \frac{{{A}_{2}}}{{{A}_{1}}} \right)}^{1/3}}={{\left( \frac{206}{4} \right)}^{1/3}}\] \[\therefore {{r}_{2}}=3{{\left( \frac{206}{4} \right)}^{1/3}}=11.6\ Fermi\].You need to login to perform this action.
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