A) 19.6 MeV
B) 2.4 MeV
C) 8.4 MeV
D) 17.3 MeV
Correct Answer: D
Solution :
B.E. of \[L{{i}^{7}}=39.20\ MeV\]and \[H{{e}^{4}}=28.24\ MeV\] Hence binding energy of \[2H{{e}^{4}}=56.48\ MeV\] Energy of reaction \[=56.48-39.20=17.28\ MeV\].You need to login to perform this action.
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