A) \[9\times {{10}^{10}}J\]
B) \[9\times {{10}^{11}}J\]
C) \[9\times {{10}^{12}}J\]
D) \[9\times {{10}^{13}}J\]
Correct Answer: D
Solution :
\[E=\Delta m{{c}^{2}},\ \Delta m=\frac{0.1}{100}={{10}^{-3}}kg\] \[\therefore E={{10}^{-3}}\times {{(3\times {{10}^{8}})}^{2}}={{10}^{-3}}\times 9\times {{10}^{16}}=9\times {{10}^{13}}J\].
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