Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन
JEE Main & Advanced
Chemistry
Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन
Question Bank
Nucleus (Stability and Reaction)
question_answer
In the sequence of following nuclear reactions \[_{92}{{X}^{238}}\xrightarrow{-\alpha }Y\xrightarrow{-\beta }Z\xrightarrow{-\beta }L{{\xrightarrow{-n\alpha }}_{84}}{{M}^{218}}\] The value of \[n\] will be [MP PMT 1999]
A) 3
B) 4
C) 5
D) 6
Correct Answer:
B
Solution :
The value of \[n=\frac{238-218}{4}=\frac{20}{4}=5-1=4\]